murlA tiny wrapper for the Python module urlparse | |
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murl Ranking & Summary
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- License:
- MPL
- Price:
- FREE
- Publisher Name:
- Berker Peksag
- Publisher web site:
- https://github.com/berkerpeksag/
murl Tags
murl Description
murl is a tiny wrapper for the Python module urlparse.InstallationTo install murl, simply: pip install murlUsagefrom murl import Urlurl = Url('https://bugzilla.mozilla.org/show_bug.cgi?id=698201#c0')print url.scheme, url.host, url.querystring, url.fragment# https bugzilla.mozilla.org id=698201 c0url.scheme = 'http'url.host = 'bugzilla.webkit.org'print urlprint url.urlprint url.schemeprint url.hostprint url.netlocprint url.host == url.netloc# http://bugzilla.webkit.org/show_bug.cgi?id=698201#c0# http://bugzilla.webkit.org/show_bug.cgi?id=698201#c0# http# bugzilla.webkit.org# bugzilla.webkit.org# Trueurl.path = 'list_bugs.cgi'print url.path, url.url# list_bugs.cgi http://bugzilla.webkit.org/list_bugs.cgi?id=698201#c0url.fragment = 'c1'print url.fragmentprint url.url# c1# http://bugzilla.webkit.org/list_bugs.cgi?id=698201#c1url.fragment = ''print url.fragmentprint url.url# ''# http://bugzilla.webkit.org/list_bugs.cgi?id=698201Product's homepage
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